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9x^2-59x+50=0
a = 9; b = -59; c = +50;
Δ = b2-4ac
Δ = -592-4·9·50
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-59)-41}{2*9}=\frac{18}{18} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-59)+41}{2*9}=\frac{100}{18} =5+5/9 $
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